How do you use half angle formula to find ##sin 67.5##?...
How do you use half angle formula to find ##sin 67.5##?
The half of ##135^o## is ##67.5^o##
Using the Half Angle Formula:
##sin (theta/2) = +-sqrt((1-costheta)/2)##
##sin (135^o/2) = +-sqrt((1-cos135^o)/2)##
##cos135^o = cos(90^o +45^o)= cos90^ocos45^o-...
