How do you solve for x in ##1/3lnx+ln2-ln3=3##?...
How do you solve for x in ##1/3lnx+ln2-ln3=3##?
The answer is: ##x=27/8e^9##.
First of all we have to add a condition otherwise our equation loses meaning: ##x>0##.
Than:
##1/3lnx+ln2-ln3=3rArrlnx=3(ln3-ln2+3)rArr##
##lnx=3(ln3-ln2+lne^3)rArrlnx=3l...
